Normal Distributions
A mathematical model for a random variable.
Describes how likely different random values are.
Discrete variables:
Continuous variables:
Empirical Rule for normal distribution:
approximately 68% of the values are within 1 SD of the mean
approximately 95% of the values are within 2 SDs of the mean
approximately 99.7% of the values are within 3 SDs of the mean
68-95-99.7
The distribution of test scores on the SAT and the ACT are both nearly normal.
Suppose that one student scores an 1800 on the SAT (Student A) and another student scores a 24 on the ACT (Student B). Which student performed better?
The standard normal distribution is defined as a normal distribution with mean 0 and standard deviation 1. It is often denoted as \(Z \sim N(0, 1)\).
Any normal random variable \(X \sim N(\mu, \sigma)\) can be transformed into a standard normal random variable \(Z\).
\[Z = \dfrac{X - \mu}{\sigma}\]
\[X = \mu + Z\sigma\]
SAT scores are \(N(1500, 300)\). ACT scores are \(N(21,5)\).
\(x_A\) represents the score of Student A; \(x_B\) represents the score of Student B.
\[z_{A} = \frac{x_{A} - \mu_{SAT}}{\sigma_{SAT}} = \frac{1800-1500}{300} = 1\]
\[z_{B} = \frac{x_{B} - \mu_{ACT}}{\sigma_{ACT}} = \frac{24 - 21}{5} = 0.6\]
What is the percentile rank for a student who scores an 1800 on the SAT for a year in which the scores are \(N(1500, 300)\)?
What is the probability that, if we randomly select a student that took the exam that year, their score would be less than 1800?
Standard normal distribution table
Calculate a \(Z\)-score.
\[Z = \frac{X - \mu}{\sigma}\]
The table gives you the area to the left of that \(z\)-score.
What is the percentile rank for a student who scores an 1800 on the SAT for a year in which the scores are \(N(1500, 300)\)?
What is the percentile rank for a student who scores an 24 on the ACT for a year in which the scores are \(N(21, 5)\)?
Find the probability that \(X {\color{red}\ge} 17.5\) if \(X \sim N(13, 2.7)\)
Calculate the \(z\)-score:
\[z = \frac{17.5 - 13}{2.7} = 1.6666667\]
Now we need to find the area to the right of 1.6666667 under the standard normal curve.
Area to the right of 17.5.
Area to the right of 1.6666667.
The total area under the normal curve is always 1.
All we need to do is subtract:
area to the right = 1 - area to the left
Finally, we can find the area to the right of 1.67.